You are right in that the rotation will never hit zero exactly, due to float values being used. You also have the issue of using `transform.Rotate.y` which should give you an error but does not for some reason (it should be transform.[localEulerAngles][1].y). You also need to prevent the barrel from being rotated too far.
Here is a rewritted (untested) function for you (I also took the liberty of making it move in the best direction to get back to 0 the fastest).
function resetBarrel(){
print("resetting barrel");
var epsilon : float = 0.001f;
var currentAngle : float = transform.localEulerAngles.y;
if (currentAngle < 360 - epsilon && currentAngle > epsilon) {
print("barrel isnt at 0");
var angleDelta : float = Time.deltaTime * 40;
// positive if forward; negative if backward (rotation wise)
var rotMultiplier : int = (currentAngle > 180) ? 1 : -1;
var resultAngle : float =
Mathf.Clamp(currentAngle + rotMultiplier * angleDelta, 0, 360);
var rotation : Vector3 = transform.localEulerAngles;
rotation.y = resultAngle;
transform.localEulerAngles = rotation;
}
else {
print("barrel at 0");
}
}
Again, this is untested so there might be some lurking syntax/logic errors in here. The `(currentAngle > 180) ? 1 : -1` part is so it rotates in the best direction (to get to 0 the fastest). If you don't want that behavior, get rid of the variable (and remove the reference to it in the `Mathf.Clamp` line).
[1]: http://unity3d.com/support/documentation/ScriptReference/Transform-localEulerAngles.html
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